BetterPhoto Q&A
Category: New Questions

Photography Question 
Carl W. Warren
BetterPhoto Member Since: 8/31/2006

Scanning for 8x10 Photos

What is the best size for 8x10 from scanned color negatives? Right now, I scan the 35mm film @ 1200 dpi and then when I use the preset crop control, then I can only fit so much of the photo that way. I would like to fit as much of the photos with out cropping before printing. If I send these to an Internet lab, they come back cropped with sometimes a vital part of the photo missing. Any help would be appreciated!

To love this question, log in above
4/1/2007 6:12:28 PM

doug Nelson
  Scan at 2400 ppi at least. Scanning at 2700 or 3200 will give you some leeway for cropping, so that you will end up with the ideal 8 x 10 at 300 ppi, when you go into Image Size and scale it out. Go into Image, Image Size, Resample UNchecked, Constrain Proportions checked. Enter 10" as your image length, 10 as image height, if a vertical. Then you can crop off the ends. This often works for me, because I think the 35mm frame is too long (or too tall), anyway. Or you can enter the short dimension as 8" and work from there.

To love this comment, log in above
4/2/2007 1:11:41 PM

Bob Fately   Carl, Doug gives some good advice - you want to scan at a high resolution (well, bove 4000dpi is probably not worthwhile) to give you the ability to crop or manipulate as necessary.

However, as for your cropped edges issue - understand that the size of the negative is 24x36MM, meaning a ration of 1:1.5. If you want to print the full frame of a 35MM film image, you need to maintain that 1.5 ratio, with in the case of an 8 inch height would translate into a 12 inch width.

To love this comment, log in above
4/2/2007 4:23:35 PM

Carl W. Warren
BetterPhoto Member Since: 8/31/2006
  thank you doug and bob, I will be needing a new computer mine just can,t handle that much right now thanks the advice will be put to good use
carl warren

To love this comment, log in above
4/2/2007 7:31:19 PM

Log in to respond or ask your own question.